What is expand (e^x+e^{-x})sin(x) ?

The solution to expand (e^x+e^{-x})sin(x) is e^xsin(x)+e^{-x}sin(x)

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expand (e^x+e^{-x})sin(x)

expand

(e^{x} + e^{- x}) sin (x)

e^{x} sin (x) + e^{- x} sin (x)

Solution steps

(e^{x} + e^{- x}) sin (x)

= sin (x) (e^{x} + e^{- x})

Apply the distributive law:

a (b + c) = ab + a c

a = sin (x), b = e^{x}, c = e^{- x}

= sin (x) e^{x} + sin (x) e^{- x}

= e^{x} sin (x) + e^{- x} sin (x)

\frac{2 x}{( 0.5 - x ) ( 1.5 - 3 x )}

\frac{2 s ^{2} - 1}{s ( s ^{2} + s )}

\frac{6}{( s + 6 ) ^{3}}

- π sin (\frac{1}{2 π} (t - 1))

\frac{2 ( - 4 π - 9 )}{3 π}

What is expand (e^x+e^{-x})sin(x) ?
The solution to expand (e^x+e^{-x})sin(x) is e^xsin(x)+e^{-x}sin(x)