What are the solutions to the equation x^2-4x-3=0 ?

The solutions to the equation x^2-4x-3=0 are x=2+sqrt(7),x=2-sqrt(7)

Find the zeros of x^2-4x-3=0

The zeros of x^2-4x-3=0 are x=2+sqrt(7),x=2-sqrt(7)

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x^{2} - 4 x - 3 = 0

x = 2 + 7, x = 2 - 7

Solution steps

x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 3) = 27

x_{1, 2} = \frac{- ( - 4 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 7}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 7}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 7}{2 \cdot 1} : 2 + 7

x = \frac{- ( - 4 ) - 2 7}{2 \cdot 1} : 2 - 7

The solutions to the quadratic equation are:

x = 2 + 7, x = 2 - 7

- 3 - 1

8 x^{3} + 125

∣ 2 x - 9 ∣ \leq 13

2 a^{- 5} b^{6} \cdot 5 a^{2} b^{2}

(\frac{8}{27})^{- \frac{2}{3}}

What are the solutions to the equation x^2-4x-3=0 ?
The solutions to the equation x^2-4x-3=0 are x=2+sqrt(7),x=2-sqrt(7)
Find the zeros of x^2-4x-3=0
The zeros of x^2-4x-3=0 are x=2+sqrt(7),x=2-sqrt(7)