What is expand 2(3x-1)^2e^{2x+1} ?

The solution to expand 2(3x-1)^2e^{2x+1} is 18e^{2x+1}x^2-12e^{2x+1}x+2e^{2x+1}

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expand 2(3x-1)^2e^{2x+1}

expand

2 (3 x - 1)^{2} e^{2 x + 1}

18 e^{2 x + 1} x^{2} - 12 e^{2 x + 1} x + 2 e^{2 x + 1}

Solution steps

2 (3 x - 1)^{2} e^{2 x + 1}

(3 x - 1)^{2} = 9 x^{2} - 6 x + 1

= 2 e^{2 x + 1} (9 x^{2} - 6 x + 1)

= 2 e^{2 x + 1} (9 x^{2} - 6 x + 1)

Distribute parentheses

= 2 e^{2 x + 1} \cdot 9 x^{2} + 2 e^{2 x + 1} (- 6 x) + 2 e^{2 x + 1} \cdot 1

Apply minus-plus rules

+ (- a) = - a

= 2 \cdot 9 e^{2 x + 1} x^{2} - 2 \cdot 6 e^{2 x + 1} x + 2 \cdot 1 \cdot e^{2 x + 1}

Simplify

2 \cdot 9 e^{2 x + 1} x^{2} - 2 \cdot 6 e^{2 x + 1} x + 2 \cdot 1 \cdot e^{2 x + 1} : 18 e^{2 x + 1} x^{2} - 12 e^{2 x + 1} x + 2 e^{2 x + 1}

= 18 e^{2 x + 1} x^{2} - 12 e^{2 x + 1} x + 2 e^{2 x + 1}

u (- t - π)

\frac{4 x ^{2}}{( 5 x + 3 ) ^{2}}

(1 + n u m) \cdot \frac{,}{2}

(2 e + 7) (2 e - 7)

\frac{6}{( k ( k + 1 ) ( k + 2 ) )}

What is expand 2(3x-1)^2e^{2x+1} ?
The solution to expand 2(3x-1)^2e^{2x+1} is 18e^{2x+1}x^2-12e^{2x+1}x+2e^{2x+1}