What is expand (2x-1)/((x-2)(x-3)(x-1)) ?

The solution to expand (2x-1)/((x-2)(x-3)(x-1)) is (2x-1)/(x^3-6x^2+11x-6)

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expand (2x-1)/((x-2)(x-3)(x-1))

expand

\frac{2 x - 1}{( x - 2 ) ( x - 3 ) ( x - 1 )}

\frac{2 x - 1}{x ^{3} - 6 x ^{2} + 11 x - 6}

Solution steps

\frac{2 x - 1}{( x - 2 ) ( x - 3 ) ( x - 1 )}

Expand

(x - 2) (x - 3) (x - 1) : x^{3} - 6 x^{2} + 11 x - 6

= \frac{2 x - 1}{x ^{3} - 6 x ^{2} + 11 x - 6}

(\frac{x ^{2} + x}{x})^{2}

e^{x} (e^{2} x + 1)^{3}

\frac{2}{( x ^{2} + 1 ) ^{2}}

\frac{5 x ^{2} - 16 x + 2}{3 x ( x - 1 )}

- \frac{u}{( u - 1 ) ^{2}}

What is expand (2x-1)/((x-2)(x-3)(x-1)) ?
The solution to expand (2x-1)/((x-2)(x-3)(x-1)) is (2x-1)/(x^3-6x^2+11x-6)