What is expand 1/(3^x(3^{2-x)+1)} ?

The solution to expand 1/(3^x(3^{2-x)+1)} is 1/(9+3^x)

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expand 1/(3^x(3^{2-x)+1)}

expand

\frac{1}{3 ^{x} ( 3 ^{2 - x} + 1 )}

\frac{1}{9 + 3 ^{x}}

Solution steps

\frac{1}{3 ^{x} ( 3 ^{2 - x} + 1 )}

Expand

3^{x} (3^{2 - x} + 1) : 9 + 3^{x}

= \frac{1}{9 + 3 ^{x}}

\frac{( k ( k + 1 ) ( 2 k + 1 ) )}{6}

\frac{1}{( x ^{2} - b ^{2} ) ^{2}}

(9 - 2 x)^{2} (x) 0

(A - B) \circ - B

(O e + De) (D i + O i)

What is expand 1/(3^x(3^{2-x)+1)} ?
The solution to expand 1/(3^x(3^{2-x)+1)} is 1/(9+3^x)