What is expand ((x-2)(x-3))/((x-1)(x+2)) ?

The solution to expand ((x-2)(x-3))/((x-1)(x+2)) is (x^2-5x+6)/(x^2+x-2)

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expand ((x-2)(x-3))/((x-1)(x+2))

expand

\frac{( x - 2 ) ( x - 3 )}{( x - 1 ) ( x + 2 )}

\frac{x ^{2} - 5 x + 6}{x ^{2} + x - 2}

Solution steps

\frac{( x - 2 ) ( x - 3 )}{( x - 1 ) ( x + 2 )}

Expand

(x - 1) (x + 2) : x^{2} + x - 2

= \frac{( x - 2 ) ( x - 3 )}{x ^{2} + x - 2}

Expand

(x - 2) (x - 3) : x^{2} - 5 x + 6

= \frac{x ^{2} - 5 x + 6}{x ^{2} + x - 2}

(e u + e + 1)^{2}

\frac{x + 9}{x ( x + 1 ) ^{2}}

(A x + B) e^{4 x}

\frac{4 ( x ^{0.5} - 3 ) ^{2}}{x}

s^{2} - k (1 - e^{s T})

What is expand ((x-2)(x-3))/((x-1)(x+2)) ?
The solution to expand ((x-2)(x-3))/((x-1)(x+2)) is (x^2-5x+6)/(x^2+x-2)