What is expand 1/((2k+1)(2k+3)) ?

The solution to expand 1/((2k+1)(2k+3)) is 1/(4k^2+8k+3)

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expand 1/((2k+1)(2k+3))

expand

\frac{1}{( 2 k + 1 ) ( 2 k + 3 )}

\frac{1}{4 k ^{2} + 8 k + 3}

Solution steps

\frac{1}{( 2 k + 1 ) ( 2 k + 3 )}

Expand

(2 k + 1) (2 k + 3) : 4 k^{2} + 8 k + 3

= \frac{1}{4 k ^{2} + 8 k + 3}

3 c - 7

\frac{9}{( s + 2 ) ( s + 4 )}

(a + e b + e^{2} c)^{3}

(ln (x) - 15)^{2}

\frac{( 1 + s ) ^{4}}{p ^{2} n ^{2}}

What is expand 1/((2k+1)(2k+3)) ?
The solution to expand 1/((2k+1)(2k+3)) is 1/(4k^2+8k+3)