What is expand (b^2c)/((a-b)(a-c)(b+c)) ?

The solution to expand (b^2c)/((a-b)(a-c)(b+c)) is (b^2c)/(b^2c+bc^2+ba^2-2bca-b^2a+ca^2-c^2a)

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expand (b^2c)/((a-b)(a-c)(b+c))

expand

\frac{b ^{2} c}{( a - b ) ( a - c ) ( b + c )}

\frac{b ^{2} c}{b ^{2} c + b c ^{2} + b a ^{2} - 2 b c a - b ^{2} a + c a ^{2} - c ^{2} a}

Solution steps

\frac{b ^{2} c}{( a - b ) ( a - c ) ( b + c )}

Expand

(a - b) (a - c) (b + c) : b^{2} c + b c^{2} + b a^{2} - 2 b c a - b^{2} a + c a^{2} - c^{2} a

= \frac{b ^{2} c}{b ^{2} c + b c ^{2} + b a ^{2} - 2 b c a - b ^{2} a + c a ^{2} - c ^{2} a}

\frac{8 ^{5}}{8 ^{3}}

(5 + 2) π

(- x + y = 2,) (x + 3 y = - 8)

d x (3 x^{2} y + 2 x)

(2 y^{'} (x) - 4) (y + 2 x)

What is expand (b^2c)/((a-b)(a-c)(b+c)) ?
The solution to expand (b^2c)/((a-b)(a-c)(b+c)) is (b^2c)/(b^2c+bc^2+ba^2-2bca-b^2a+ca^2-c^2a)