What is expand (n-k-1)!*(n-k) ?

The solution to expand (n-k-1)!*(n-k) is n(n-k-1)!-k(n-k-1)!

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expand (n-k-1)!*(n-k)

expand

(n - k - 1)! \cdot (n - k)

n (n - k - 1)! - k (n - k - 1)!

Solution steps

(n - k - 1)! (n - k)

Apply the distributive law:

a (b - c) = ab - a c

a = (n - k - 1)!, b = n, c = k

= (n - k - 1)! n - (n - k - 1)! k

= n (n - k - 1)! - k (n - k - 1)!

i e^{- (1 + i) t}

(x - e^{x} sin (y)) d y

x - 1 (1 - 6) - 6

\frac{u ( - 2 u - 3 )}{1 + 2 u}

\frac{x ( x - 3 )}{( x + 5 ) ( x - 2 )}

What is expand (n-k-1)!*(n-k) ?
The solution to expand (n-k-1)!*(n-k) is n(n-k-1)!-k(n-k-1)!