What is expand 3(c_{1}e^{-3x}+2c_{3}xe^{-3x}) ?

The solution to expand 3(c_{1}e^{-3x}+2c_{3}xe^{-3x}) is 3c_{1}e^{-3x}+6c_{3}e^{-3x}x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 3(c_{1}e^{-3x}+2c_{3}xe^{-3x})

expand

3 (c_{1} e^{- 3 x} + 2 c_{3} x e^{- 3 x})

3 c_{1} e^{- 3 x} + 6 c_{3} e^{- 3 x} x

Solution steps

3 (c_{1} e^{- 3 x} + 2 c_{3} x e^{- 3 x})

= 3 (c_{1} e^{- 3 x} + 2 c_{3} e^{- 3 x} x)

Apply the distributive law:

a (b + c) = ab + a c

a = 3, b = c_{1} e^{- 3 x}, c = 2 c_{3} x e^{- 3 x}

= 3 c_{1} e^{- 3 x} + 3 \cdot 2 c_{3} x e^{- 3 x}

= 3 c_{1} e^{- 3 x} + 3 \cdot 2 c_{3} e^{- 3 x} x

Multiply the numbers:

3 \cdot 2 = 6

= 3 c_{1} e^{- 3 x} + 6 c_{3} e^{- 3 x} x

- 98

\frac{( e ^{x} )}{( x + 12 ) ^{3}}

\frac{( x + a ) ^{2}}{x ^{2} + 3}

(π + \frac{π}{6}) \cdot 2

A (1, 3) y B (2, - 7)

What is expand 3(c_{1}e^{-3x}+2c_{3}xe^{-3x}) ?
The solution to expand 3(c_{1}e^{-3x}+2c_{3}xe^{-3x}) is 3c_{1}e^{-3x}+6c_{3}e^{-3x}x