What is expand 1/(x^2(x^2-4)^2) ?

The solution to expand 1/(x^2(x^2-4)^2) is 1/(x^6-8x^4+16x^2)

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expand 1/(x^2(x^2-4)^2)

expand

\frac{1}{x ^{2} ( x ^{2} - 4 ) ^{2}}

\frac{1}{x ^{6} - 8 x ^{4} + 16 x ^{2}}

Solution steps

\frac{1}{x ^{2} ( x ^{2} - 4 ) ^{2}}

(x^{2} - 4)^{2} = x^{4} - 8 x^{2} + 16

= \frac{1}{x ^{2} ( x ^{4} - 8 x ^{2} + 16 )}

Expand

x^{2} (x^{4} - 8 x^{2} + 16) : x^{6} - 8 x^{4} + 16 x^{2}

= \frac{1}{x ^{6} - 8 x ^{4} + 16 x ^{2}}

(0.685 = 805 x + 40 y) 60

\frac{( x + 1 ) ( 2 x + 1 )}{10 x ( x - 3 )}

2 \frac{d}{d x} (w (1 - x))

\frac{- 5 x - 19}{( x - 1 ) ( x - 7 )}

v (2 - sin (\frac{π ( t - 60 )}{120}))

What is expand 1/(x^2(x^2-4)^2) ?
The solution to expand 1/(x^2(x^2-4)^2) is 1/(x^6-8x^4+16x^2)