What is expand-1/((s^2+1)(s+3)(s+1)) ?

The solution to expand-1/((s^2+1)(s+3)(s+1)) is -1/(s^4+4s^3+4s^2+4s+3)

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expand-1/((s^2+1)(s+3)(s+1))

expand

- \frac{1}{( s ^{2} + 1 ) ( s + 3 ) ( s + 1 )}

- \frac{1}{s ^{4} + 4 s ^{3} + 4 s ^{2} + 4 s + 3}

Solution steps

- \frac{1}{( s ^{2} + 1 ) ( s + 3 ) ( s + 1 )}

Expand

(s^{2} + 1) (s + 3) (s + 1) : s^{4} + 4 s^{3} + 4 s^{2} + 4 s + 3

= - \frac{1}{s ^{4} + 4 s ^{3} + 4 s ^{2} + 4 s + 3}

(e^{2 x} - 1) (e^{2 y} + 1)

ro t (2 x y, x^{2} + z^{2}, 2 yz)

\frac{x}{y ( x y + y ) ( x - 1 )}

6 (- 4 x + 6 y = - 2)

e^{(1.5 t - 9)} u (- 0.5 t + 3)

What is expand-1/((s^2+1)(s+3)(s+1)) ?
The solution to expand-1/((s^2+1)(s+3)(s+1)) is -1/(s^4+4s^3+4s^2+4s+3)