What are the solutions to the equation 8x^2+4=0 ?

The solutions to the equation 8x^2+4=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i

Find the zeros of 8x^2+4=0

The zeros of 8x^2+4=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i

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8 x^{2} + 4 = 0

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

8 x^{2} + 4 = 0

Move

4

to the right side

8 x^{2} = - 4

Divide both sides by

8

x^{2} = - \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{2}, x = - - \frac{1}{2}

- \frac{1}{2} = \frac{1}{2} i

- - \frac{1}{2} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

- \frac{3}{4} m - 18 \leq - \frac{1}{4}

1 - 64 x^{3}

\frac{x y ^{3} - 9 x y}{12 x y ^{2} + 12 x y - 144 x}

\frac{4 x y}{2 x}

9 v^{2} + 6 v + 1

What are the solutions to the equation 8x^2+4=0 ?
The solutions to the equation 8x^2+4=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i
Find the zeros of 8x^2+4=0
The zeros of 8x^2+4=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i