What is expand (9s-31)/((s-3)(s-4)) ?

The solution to expand (9s-31)/((s-3)(s-4)) is (9s-31)/(s^2-7s+12)

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expand (9s-31)/((s-3)(s-4))

expand

\frac{9 s - 31}{( s - 3 ) ( s - 4 )}

\frac{9 s - 31}{s ^{2} - 7 s + 12}

Solution steps

\frac{9 s - 31}{( s - 3 ) ( s - 4 )}

Expand

(s - 3) (s - 4) : s^{2} - 7 s + 12

= \frac{9 s - 31}{s ^{2} - 7 s + 12}

t (2 t, - 5, t^{2})

\frac{x ^{2} + 3 x - 16}{( x + 7 ) ( x + 5 )}

\frac{3 x + 4}{( x + 2 ) ^{2}}

\frac{14 x - 2}{5 \cdot ( 5 + 35 x )}

- \frac{1}{( n + 1 ) ( n + 2 )}

What is expand (9s-31)/((s-3)(s-4)) ?
The solution to expand (9s-31)/((s-3)(s-4)) is (9s-31)/(s^2-7s+12)