What is expand (9x+3)/((x+1)(x-1)) ?

The solution to expand (9x+3)/((x+1)(x-1)) is (9x+3)/(x^2-1)

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expand (9x+3)/((x+1)(x-1))

expand

\frac{9 x + 3}{( x + 1 ) ( x - 1 )}

\frac{9 x + 3}{x ^{2} - 1}

Solution steps

\frac{9 x + 3}{( x + 1 ) ( x - 1 )}

Expand

(x + 1) (x - 1) : x^{2} - 1

= \frac{9 x + 3}{x ^{2} - 1}

(50 - x) x d x

12 [k (k^{2} - 4 k + 1)]

(x^{4} + 2 y) d x - x d x

\frac{d y}{d x}, y^{2} = x^{2} - 2 x

\frac{3 x ^{2} + 8 x + 2}{x ( x + 1 ) ^{2}}

What is expand (9x+3)/((x+1)(x-1)) ?
The solution to expand (9x+3)/((x+1)(x-1)) is (9x+3)/(x^2-1)