What is expand 3(7-9k+23k=4k-(24-k)) ?

The solution to expand 3(7-9k+23k=4k-(24-k)) is 21+42k=7k-72

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expand 3(7-9k+23k=4k-(24-k))

expand

3 (7 - 9 k + 23 k = 4 k - (24 - k))

21 + 42 k = 7 k - 72

Solution steps

3 (7 - 9 k + 23 k = 4 k - (24 - k))

= 3 (7 - 9 k + 23 \cdot 4 = kk - (24 - k))

Distribute parentheses

3 \cdot 7 + 3 (- 9 k) + 3 \cdot 23 k = 4 k + 3 (- (24 - k))

Apply minus-plus rules

+ (- a) = - a

3 \cdot 7 - 3 \cdot 9 k + 3 \cdot 23 k = 4 k - 3 (24 - k)

Simplify

3 \cdot 7 - 3 \cdot 9 k + 3 \cdot 23 k = 4 k - 3 (24 - k) : 21 + 42 k = 7 k - 72

21 + 42 k = 7 k - 72

(x - 75) (tan (3 5^{\circ}))

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b (\frac{t - s}{- b})

(\frac{π}{4} - \frac{1}{2}) 400

What is expand 3(7-9k+23k=4k-(24-k)) ?
The solution to expand 3(7-9k+23k=4k-(24-k)) is 21+42k=7k-72