What is the answer to 4(t-2)+3(t-2)-2t+4(t-2+t)=-2 ?

The answer to 4(t-2)+3(t-2)-2t+4(t-2+t)=-2 is t= 20/13

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4(t-2)+3(t-2)-2t+4(t-2+t)=-2

4 (t - 2) + 3 (t - 2) - 2 t + 4 (t - 2 + t) = - 2

t = \frac{20}{13}

Solution steps

4 (t - 2) + 3 (t - 2) - 2 t + 4 (t - 2 + t) = - 2

Add similar elements:

4 (t - 2) + 3 (t - 2) = 7 (t - 2)

7 (t - 2) - 2 t + 4 (t + t - 2) = - 2

Simplify

t - 2 + t : 2 t - 2

7 (t - 2) - 2 t + 4 (2 t - 2) = - 2

Expand

7 (t - 2) - 2 t + 4 (2 t - 2) : 13 t - 22

13 t - 22 = - 2

Move

22

to the right side

13 t = 20

Divide both sides by

13

t = \frac{20}{13}

4 m^{(5 - 3)} + 5 m^{(3 - 2)} + 3 m

3 (w + 5) = 33

3 (x + 1) + 3 \geq 2 x + 8

(64)^{\frac{2}{3}}

0.5 x \leq 4

What is the answer to 4(t-2)+3(t-2)-2t+4(t-2+t)=-2 ?
The answer to 4(t-2)+3(t-2)-2t+4(t-2+t)=-2 is t= 20/13
Solve for t: 4(t-2)+3(t-2)-2t+4(t-2+t)=-2
The solution is t= 20/13