What is expand y(xy+y)(x-1)y'(x) ?

The solution to expand y(xy+y)(x-1)y'(x) is x^2y'(x)y^2-y'(x)y^2

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expand y(xy+y)(x-1)y'(x)

expand

y (x y + y) (x - 1) y^{'} (x)

x^{2} y' (x) y^{2} - y' (x) y^{2}

Solution steps

y (x y + y) (x - 1) y^{'} (x)

Expand

(x y + y) (x - 1) : x^{2} y - y

= y y^{'} (x) (x^{2} y - y)

Expand

y y^{'} (x) (x^{2} y - y) : x^{2} y^{'} (x) y^{2} - y^{'} (x) y^{2}

= x^{2} y^{'} (x) y^{2} - y^{'} (x) y^{2}

(e^{x y} + e^{y})^{4}

\frac{1}{12} e^{4 x} (2 x - 1)

(x ln (x) + x y) d y

\frac{1}{x ( 10 + s )}

(e^{x} + y) d x

What is expand y(xy+y)(x-1)y'(x) ?
The solution to expand y(xy+y)(x-1)y'(x) is x^2y'(x)y^2-y'(x)y^2