What is expand (ae^3-2a^2+4)(ae^3-3a) ?

The solution to expand (ae^3-2a^2+4)(ae^3-3a) is e^6a^2-3e^3a^2-2e^3a^3+6a^3+4e^3a-12a

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expand (ae^3-2a^2+4)(ae^3-3a)

expand

(a e^{3} - 2 a^{2} + 4) (a e^{3} - 3 a)

e^{6} a^{2} - 3 e^{3} a^{2} - 2 e^{3} a^{3} + 6 a^{3} + 4 e^{3} a - 12 a

Solution steps

(a e^{3} - 2 a^{2} + 4) (a e^{3} - 3 a)

= (e^{3} a - 2 a^{2} + 4) (e^{3} a - 3 a)

Distribute parentheses

= a e^{3} a e^{3} + a e^{3} (- 3 a) + (- 2 a^{2}) a e^{3} + (- 2 a^{2}) (- 3 a) + 4 a e^{3} + 4 (- 3 a)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= e^{3} e^{3} aa - 3 e^{3} aa - 2 e^{3} a^{2} a + 2 \cdot 3 a^{2} a + 4 e^{3} a - 4 \cdot 3 a

Simplify

e^{3} e^{3} aa - 3 e^{3} aa - 2 e^{3} a^{2} a + 2 \cdot 3 a^{2} a + 4 e^{3} a - 4 \cdot 3 a : e^{6} a^{2} - 3 e^{3} a^{2} - 2 e^{3} a^{3} + 6 a^{3} + 4 e^{3} a - 12 a

= e^{6} a^{2} - 3 e^{3} a^{2} - 2 e^{3} a^{3} + 6 a^{3} + 4 e^{3} a - 12 a

\frac{2}{( 4 + h ) ^{2}}

(a - 2, b - 2) (\frac{b}{a})^{3}

3 \cdot 10.2

(28 = 6, x - 7 y) - (5 x = - 7 y + 49)

x + 2 ((x + 1) (x - 1))

What is expand (ae^3-2a^2+4)(ae^3-3a) ?
The solution to expand (ae^3-2a^2+4)(ae^3-3a) is e^6a^2-3e^3a^2-2e^3a^3+6a^3+4e^3a-12a