What is expand (x(19x^2+12))/3 ?

The solution to expand (x(19x^2+12))/3 is (19x^3)/3+4x

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expand (x(19x^2+12))/3

expand

\frac{x ( 19 x ^{2} + 12 )}{3}

\frac{19 x ^{3}}{3} + 4 x

Solution steps

\frac{x ( 19 x ^{2} + 12 )}{3}

Expand

x (19 x^{2} + 12) : 19 x^{3} + 12 x

= \frac{19 x ^{3} + 12 x}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{19 x ^{3} + 12 x}{3} = \frac{19 x ^{3}}{3} + \frac{12 x}{3}

= \frac{19 x ^{3}}{3} + \frac{12 x}{3}

Divide the numbers:

\frac{12}{3} = 4

= \frac{19 x ^{3}}{3} + 4 x

\frac{x ^{2} - 10 x + 31}{( x - 5 ) ^{2}}

\frac{1}{( 2 n - 1 ) ^{2}}

- 0.1249 (z - 1) (z - e^{- 9.9975 T})

5 7^{2} - 5 5^{2}

(3, 4, - 6) x (- 3, 1, 0)

What is expand (x(19x^2+12))/3 ?
The solution to expand (x(19x^2+12))/3 is (19x^3)/3+4x