What is expand ((x-3)*(x+4))/(x^2) ?

The solution to expand ((x-3)*(x+4))/(x^2) is 1+1/x-(12)/(x^2)

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expand ((x-3)*(x+4))/(x^2)

expand

\frac{( x - 3 ) \cdot ( x + 4 )}{x ^{2}}

1 + \frac{1}{x} - \frac{12}{x ^{2}}

Solution steps

\frac{( x - 3 ) ( x + 4 )}{x ^{2}}

Expand

(x - 3) (x + 4) : x^{2} + x - 12

= \frac{x ^{2} + x - 12}{x ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} + x - 12}{x ^{2}} = \frac{x ^{2}}{x ^{2}} + \frac{x}{x ^{2}} - \frac{12}{x ^{2}}

= \frac{x ^{2}}{x ^{2}} + \frac{x}{x ^{2}} - \frac{12}{x ^{2}}

Apply rule

\frac{a}{a} = 1

\frac{x ^{2}}{x ^{2}} = 1

= 1 + \frac{x}{x ^{2}} - \frac{12}{x ^{2}}

Cancel

\frac{x}{x ^{2}} : \frac{1}{x}

= 1 + \frac{1}{x} - \frac{12}{x ^{2}}

(2 x + y) d x + (3 - 3 y) d y

24 ((n + 1)!)^{3} (3 n)!

1 - [x + 1]^{2}

(2 e^{3 x} - e^{- 3 x})^{2}

\frac{1}{( a + 1 ) ^{2}}

What is expand ((x-3)*(x+4))/(x^2) ?
The solution to expand ((x-3)*(x+4))/(x^2) is 1+1/x-(12)/(x^2)