What is expand ((6-y)^3)/(3y) ?

The solution to expand ((6-y)^3)/(3y) is (72)/y-36+6y-(y^2)/3

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expand ((6-y)^3)/(3y)

expand

\frac{( 6 - y ) ^{3}}{3 y}

\frac{72}{y} - 36 + 6 y - \frac{y ^{2}}{3}

Solution steps

\frac{( 6 - y ) ^{3}}{3 y}

(6 - y)^{3} = 216 - 108 y + 18 y^{2} - y^{3}

= \frac{216 - 108 y + 18 y ^{2} - y ^{3}}{3 y}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{216 - 108 y + 18 y ^{2} - y ^{3}}{3 y} = \frac{216}{3 y} - \frac{108 y}{3 y} + \frac{18 y ^{2}}{3 y} - \frac{y ^{3}}{3 y}

= \frac{216}{3 y} - \frac{108 y}{3 y} + \frac{18 y ^{2}}{3 y} - \frac{y ^{3}}{3 y}

\frac{216}{3 y} = \frac{72}{y}

\frac{108 y}{3 y} = 36

\frac{18 y ^{2}}{3 y} = 6 y

\frac{y ^{3}}{3 y} = \frac{y ^{2}}{3}

= \frac{72}{y} - 36 + 6 y - \frac{y ^{2}}{3}

\frac{2 ( 2 x - 1 )}{3 ( x + 1 )}

\frac{2.5 ( s + 7.2 ) ( s + 6.4 )}{s}

\frac{( x ( a - b ) + b ) ^{2}}{x a - x b}

(2 x^{4} + x^{3}) d x

\frac{( x + 6 )}{( x - 1 ) ^{2}}

What is expand ((6-y)^3)/(3y) ?
The solution to expand ((6-y)^3)/(3y) is (72)/y-36+6y-(y^2)/3