What is expand (x+4)2sin(x)dx ?

The solution to expand (x+4)2sin(x)dx is 2xsin(x)dx+8sin(x)dx

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x+4)2sin(x)dx

expand

(x + 4) 2 sin (x) d x

2 x sin (x) d x + 8 sin (x) d x

Solution steps

(x + 4) \cdot 2 sin (x) d x

= 2 sin (x) (x + 4) d x

Apply the distributive law:

a (b + c) = ab + a c

a = 2 sin (x) d x, b = x, c = 4

= 2 sin (x) d xx + 2 sin (x) d x \cdot 4

= 2 x sin (x) d x + 2 \cdot 4 sin (x) d x

Multiply the numbers:

2 \cdot 4 = 8

= 2 x sin (x) d x + 8 sin (x) d x

P (- 1, - 1) y Q (7, 7)

(- 2 - - 2 i)^{6}

(e^{i x} - e^{- i x})^{4}

(y^{3})^{4}

3 x (x + x^{4}) d x

What is expand (x+4)2sin(x)dx ?
The solution to expand (x+4)2sin(x)dx is 2xsin(x)dx+8sin(x)dx