What is expand (x(5ln(x)-1))/(25) ?

The solution to expand (x(5ln(x)-1))/(25) is (xln(x))/5-x/(25)

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expand (x(5ln(x)-1))/(25)

expand

\frac{x ( 5 ln ( x ) - 1 )}{25}

\frac{x ln ( x )}{5} - \frac{x}{25}

Solution steps

\frac{x ( 5 ln ( x ) - 1 )}{25}

Expand

x (5 ln (x) - 1) : 5 x ln (x) - x

= \frac{5 x ln ( x ) - x}{25}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{5 x ln ( x ) - x}{25} = \frac{5 x ln ( x )}{25} - \frac{x}{25}

= \frac{5 x ln ( x )}{25} - \frac{x}{25}

Cancel

\frac{5 x ln ( x )}{25} : \frac{x ln ( x )}{5}

= \frac{x ln ( x )}{5} - \frac{x}{25}

\frac{1}{x ( x ^{2} - x + 1 )}

\frac{1}{( x - 1 ) ^{2} ( x ^{2} + 2 )}

\frac{x ( 100 - x )}{4}

(11 y - 13) (- 8 y + 16)

A (4, 5) B (3, - 2) C (1, - 4)

What is expand (x(5ln(x)-1))/(25) ?
The solution to expand (x(5ln(x)-1))/(25) is (xln(x))/5-x/(25)