What is expand ((3x-2)(3x+1))/3 ?

The solution to expand ((3x-2)(3x+1))/3 is 3x^2-x-2/3

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expand ((3x-2)(3x+1))/3

expand

\frac{( 3 x - 2 ) ( 3 x + 1 )}{3}

3 x^{2} - x - \frac{2}{3}

Solution steps

\frac{( 3 x - 2 ) ( 3 x + 1 )}{3}

Expand

(3 x - 2) (3 x + 1) : 9 x^{2} - 3 x - 2

= \frac{9 x ^{2} - 3 x - 2}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 x ^{2} - 3 x - 2}{3} = \frac{9 x ^{2}}{3} - \frac{3 x}{3} - \frac{2}{3}

= \frac{9 x ^{2}}{3} - \frac{3 x}{3} - \frac{2}{3}

Divide the numbers:

\frac{9}{3} = 3

= 3 x^{2} - \frac{3 x}{3} - \frac{2}{3}

Divide the numbers:

\frac{3}{3} = 1

= 3 x^{2} - x - \frac{2}{3}

(4 x^{- 1} \circ 3 x + 5) (x)

\frac{( ( x + 1 ) ( x - 2 ) )}{x - 1}

- \frac{5 m ( t + 10 s ) ^{2}}{s ^{2}}

\frac{5 x}{( x + 3 ) ^{4}}

2^{2} - 2

What is expand ((3x-2)(3x+1))/3 ?
The solution to expand ((3x-2)(3x+1))/3 is 3x^2-x-2/3