What is (5x+1\circ x^2-5)(-4) ?

The solution to (5x+1\circ x^2-5)(-4) is -4(5x+\circ x^2-5)

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simplify (5x+1\circ x^2-5)(-4)

simplify

(5 x + 1 \circ x^{2} - 5) (- 4)

- 4 (5 x + \circ x^{2} - 5)

Solution steps

(5 x + 1 \circ x^{2} - 5) (- 4)

Remove parentheses:

(- a) = - a

= - (5 x + 1 \circ x^{2} - 5) \cdot 4

Multiply:

1 \circ = \circ

= - 4 (\circ x^{2} + 5 x - 5)

(e^{2 x} + 2 x e^{2 x}) (4 x e^{2 x})

\frac{( 1 )}{( ( z + 2 ) ( z ^{(2)} + 1 ) )}

- 2 (ln (\frac{x - 2}{x + 2}) + c)

R e (x + Y)^{4}

e^{x} \cdot (x^{2} + 2 x + 3)

What is (5x+1\circ x^2-5)(-4) ?
The solution to (5x+1\circ x^2-5)(-4) is -4(5x+\circ x^2-5)