What is expand 2(1+t^2)e^{5t} ?

The solution to expand 2(1+t^2)e^{5t} is 2e^{5t}+2e^{5t}t^2

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expand 2(1+t^2)e^{5t}

expand

2 (1 + t^{2}) e^{5 t}

2 e^{5 t} + 2 e^{5 t} t^{2}

Solution steps

2 (1 + t^{2}) e^{5 t}

= 2 e^{5 t} (1 + t^{2})

Apply the distributive law:

a (b + c) = ab + a c

a = 2 e^{5 t}, b = 1, c = t^{2}

= 2 e^{5 t} \cdot 1 + 2 e^{5 t} t^{2}

= 2 \cdot 1 \cdot e^{5 t} + 2 e^{5 t} t^{2}

Multiply the numbers:

2 \cdot 1 = 2

= 2 e^{5 t} + 2 e^{5 t} t^{2}

x - (x - 1) \cdot (ln (x - 1))

\frac{10 ( y - 1 )}{x}

6 y (e^{x} + e^{x} x)

\frac{a x - b x}{( x + a ) ( x + b )}

- \frac{96}{29} (- 0.29 + 0.89 = 120)

What is expand 2(1+t^2)e^{5t} ?
The solution to expand 2(1+t^2)e^{5t} is 2e^{5t}+2e^{5t}t^2