What is the d/(dy)((x)(y-x-xy+1)) ?

The d/(dy)((x)(y-x-xy+1)) is x(-x+1)

What is the first d/(dy)((x)(y-x-xy+1)) ?

The first d/(dy)((x)(y-x-xy+1)) is x(-x+1)

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\frac{d}{d y} ((x) (y - x - x y + 1))

x (- x + 1)

Solution steps

\frac{d}{d y} ((x) (y - x - x y + 1))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d y} (y - x - x y + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{d y}{d y} - \frac{d x}{d y} - \frac{d}{d y} (x y) + \frac{d}{d y} (1))

\frac{d y}{d y} = 1

\frac{d x}{d y} = 0

\frac{d}{d y} (x y) = x

\frac{d}{d y} (1) = 0

= x (1 - 0 - x + 0)

Simplify

= x (- x + 1)

cos ((1 - k) π)

\frac{( x ^{2} - 1 ) ^{5}}{10}

x (x - a) (x - b) (x - c) + a + c

\frac{5 ( 2 a + b )}{3 b}

\frac{1}{( x - 2 ) ( a - b )}

What is the d/(dy)((x)(y-x-xy+1)) ?
The d/(dy)((x)(y-x-xy+1)) is x(-x+1)
What is the first d/(dy)((x)(y-x-xy+1)) ?
The first d/(dy)((x)(y-x-xy+1)) is x(-x+1)