What are the solutions to the equation 14z^2-10z+1=0 ?

The solutions to the equation 14z^2-10z+1=0 are z=(5+sqrt(11))/(14),z=(5-sqrt(11))/(14)

Find the zeros of 14z^2-10z+1=0

The zeros of 14z^2-10z+1=0 are z=(5+sqrt(11))/(14),z=(5-sqrt(11))/(14)

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14 z^{2} - 10 z + 1 = 0

z = \frac{5 + 11}{14}, z = \frac{5 - 11}{14}

Decimal Notation

z = 0.59404 \dots, z = 0.12024 \dots

Solution steps

14 z^{2} - 10 z + 1 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 14 \cdot 1}{2 \cdot 14}

(- 10)^{2} - 4 \cdot 14 \cdot 1 = 211

z_{1, 2} = \frac{- ( - 10 ) \pm 2 11}{2 \cdot 14}

Separate the solutions

z_{1} = \frac{- ( - 10 ) + 2 11}{2 \cdot 14}, z_{2} = \frac{- ( - 10 ) - 2 11}{2 \cdot 14}

z = \frac{- ( - 10 ) + 2 11}{2 \cdot 14} : \frac{5 + 11}{14}

z = \frac{- ( - 10 ) - 2 11}{2 \cdot 14} : \frac{5 - 11}{14}

The solutions to the quadratic equation are:

z = \frac{5 + 11}{14}, z = \frac{5 - 11}{14}

∣ x + 2 ∣ + 8 = 5

(27 b^{6})^{\frac{5}{3}}

∣ - 1 - 5 x ∣ = ∣ x - 9 ∣

- \frac{1}{9} - 1

\frac{3 x}{2} = 12

What are the solutions to the equation 14z^2-10z+1=0 ?
The solutions to the equation 14z^2-10z+1=0 are z=(5+sqrt(11))/(14),z=(5-sqrt(11))/(14)
Find the zeros of 14z^2-10z+1=0
The zeros of 14z^2-10z+1=0 are z=(5+sqrt(11))/(14),z=(5-sqrt(11))/(14)