What is expand (x-4)/(3(x^2-3x+2)) ?

The solution to expand (x-4)/(3(x^2-3x+2)) is (x-4)/(3x^2-9x+6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x-4)/(3(x^2-3x+2))

expand

\frac{x - 4}{3 ( x ^{2} - 3 x + 2 )}

\frac{x - 4}{3 x ^{2} - 9 x + 6}

Solution steps

\frac{x - 4}{3 ( x ^{2} - 3 x + 2 )}

Expand

3 (x^{2} - 3 x + 2) : 3 x^{2} - 9 x + 6

= \frac{x - 4}{3 x ^{2} - 9 x + 6}

2 ((x + h) - 2)^{2}

2 (\frac{- x - 1}{e ^{x}} - C)

1 (2 x + 4 y = 12)

f (x + 1)^{3} d x

\frac{x}{( x - 3 ) ^{5}}

What is expand (x-4)/(3(x^2-3x+2)) ?
The solution to expand (x-4)/(3(x^2-3x+2)) is (x-4)/(3x^2-9x+6)