What is expand-(3(n^2+14))/(2n-6) ?

The solution to expand-(3(n^2+14))/(2n-6) is -(3n^2+42)/(2n-6)

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expand-(3(n^2+14))/(2n-6)

expand

- \frac{3 ( n ^{2} + 14 )}{2 n - 6}

- \frac{3 n ^{2} + 42}{2 n - 6}

Solution steps

- \frac{3 ( n ^{2} + 14 )}{2 n - 6}

Expand

3 (n^{2} + 14) : 3 n^{2} + 42

= - \frac{3 n ^{2} + 42}{2 n - 6}

\frac{( s + 3 + 2 )}{s + 2}

\frac{( 4 x - 1 )}{( x + 1 ) ( x - 4 )}

\frac{( x + 7 ) ( x + 3 )}{x + 4}

\frac{x ( x + 1 )}{2} + (k + 1)

\frac{6}{s ( 0.2 s + 1 ) + 6}

What is expand-(3(n^2+14))/(2n-6) ?
The solution to expand-(3(n^2+14))/(2n-6) is -(3n^2+42)/(2n-6)