What is expand (2x+4x-3)/(x^2) ?

The solution to expand (2x+4x-3)/(x^2) is 6/x-3/(x^2)

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expand (2x+4x-3)/(x^2)

expand

\frac{2 x + 4 x - 3}{x ^{2}}

\frac{6}{x} - \frac{3}{x ^{2}}

Solution steps

\frac{2 x + 4 x - 3}{x ^{2}}

Add similar elements:

2 x + 4 x = 6 x

= \frac{6 x - 3}{x ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x - 3}{x ^{2}} = \frac{6 x}{x ^{2}} - \frac{3}{x ^{2}}

= \frac{6 x}{x ^{2}} - \frac{3}{x ^{2}}

Cancel

\frac{6 x}{x ^{2}} : \frac{6}{x}

= \frac{6}{x} - \frac{3}{x ^{2}}

- 2 (5 ln (2) - 2)

\frac{( - s - 1 )}{( s + 3 ) ^{2}}

(3 e + 8) (3 e - 8)

7 x + 1 (3, - 1)

\frac{( 2 x - 2 ) ( x + 1 )}{x + 2}

What is expand (2x+4x-3)/(x^2) ?
The solution to expand (2x+4x-3)/(x^2) is 6/x-3/(x^2)