What is expand (x+1)ln(x+1)-x ?

The solution to expand (x+1)ln(x+1)-x is xln(x+1)+ln(x+1)-x

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expand (x+1)ln(x+1)-x

expand

(x + 1) ln (x + 1) - x

x ln (x + 1) + ln (x + 1) - x

Solution steps

(x + 1) ln (x + 1) - x

= ln (x + 1) (x + 1) - x

Expand

ln (x + 1) (x + 1) : x ln (x + 1) + ln (x + 1)

= x ln (x + 1) + ln (x + 1) - x

e^{t} \cdot u (t - \frac{1}{2})

\frac{( ( x ^{2} - 1 ) )}{( x ^{2} )}

(- 1, 1, 2) x (3, 2, - 1)

(9 + e^{- 6 x})^{2}

A (- 2, 3) B (5, - 4)

What is expand (x+1)ln(x+1)-x ?
The solution to expand (x+1)ln(x+1)-x is xln(x+1)+ln(x+1)-x