What is expand (3x)/(y(x^2y^2+2xy-3)) ?

The solution to expand (3x)/(y(x^2y^2+2xy-3)) is (3x)/(x^2y^3+2xy^2-3y)

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expand (3x)/(y(x^2y^2+2xy-3))

expand

\frac{3 x}{y ( x ^{2} y ^{2} + 2 x y - 3 )}

\frac{3 x}{x ^{2} y ^{3} + 2 x y ^{2} - 3 y}

Solution steps

\frac{3 x}{y ( x ^{2} y ^{2} + 2 x y - 3 )}

Expand

y (x^{2} y^{2} + 2 x y - 3) : x^{2} y^{3} + 2 x y^{2} - 3 y

= \frac{3 x}{x ^{2} y ^{3} + 2 x y ^{2} - 3 y}

2 (x - 4 ln ∣ x + 4 ∣ + C)

20 \cdot 15

\frac{- 6 x + 14}{( x - 1 ) ^{2}}

- \frac{0.72}{( 0.6 x + 1 ) ^{2}}

\frac{e ^{- t}}{( s + 2 ) ( s + 1 )}

What is expand (3x)/(y(x^2y^2+2xy-3)) ?
The solution to expand (3x)/(y(x^2y^2+2xy-3)) is (3x)/(x^2y^3+2xy^2-3y)