What is expand 3*e^{x^2+x}*(2x+1) ?

The solution to expand 3*e^{x^2+x}*(2x+1) is 6e^{x^2+x}x+3e^{x^2+x}

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expand 3e^{x^2+x}(2x+1)

expand

3 \cdot e^{x^{2} + x} \cdot (2 x + 1)

6 e^{x^{2} + x} x + 3 e^{x^{2} + x}

Solution steps

3 e^{x^{2} + x} (2 x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = 3 e^{x^{2} + x}, b = 2 x, c = 1

= 3 e^{x^{2} + x} \cdot 2 x + 3 e^{x^{2} + x} \cdot 1

= 3 \cdot 2 e^{x^{2} + x} x + 3 \cdot 1 \cdot e^{x^{2} + x}

Simplify

3 \cdot 2 e^{x^{2} + x} x + 3 \cdot 1 \cdot e^{x^{2} + x} : 6 e^{x^{2} + x} x + 3 e^{x^{2} + x}

= 6 e^{x^{2} + x} x + 3 e^{x^{2} + x}

(\frac{- 40}{4} bi g)^{2} - (4 - 40) 2

\frac{2 ( 1 - 2 y x )}{y ( - y - 2 y x )}

\frac{3 ^{k} - 1}{3 ^{k}}

5_{2} (3_{2} + 2) - 4 (3_{2} + 2)

2 (2 + 3 i + (- 1 + 5 i) = (2 - 1) + (3 + 5) i)

What is expand 3*e^{x^2+x}*(2x+1) ?
The solution to expand 3*e^{x^2+x}*(2x+1) is 6e^{x^2+x}x+3e^{x^2+x}