What is expand (-xy'(x)-y)xy ?

The solution to expand (-xy'(x)-y)xy is -x^2yy'(x)-xy^2

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expand (-xy'(x)-y)xy

expand

(- x y^{'} (x) - y) x y

- x^{2} yy' (x) - x y^{2}

Solution steps

(- x y^{'} (x) - y) x y

= x (- x y^{^{'}} (x) - y) y

Apply the distributive law:

a (b - c) = ab - a c

a = x y, b = - x y^{'} (x), c = y

= x y (- x y^{^{'}} (x)) - x yy

Apply minus-plus rules

+ (- a) = - a

= - xx y y^{^{'}} (x) - x yy

Simplify

- xx y y^{'} (x) - x yy : - x^{2} y y^{'} (x) - x y^{2}

= - x^{2} y y^{'} (x) - x y^{2}

\frac{( 4 - x ^{2} ) ( x 3 )}{4}

8 (x + 43 = 56)

\frac{75 ( - cos ( π t ) + 1 )}{π t}

\frac{( ( x + 3 ) \cdot ( x - 4 ) )}{2}

- \frac{27 ( n + 1 )}{2}

What is expand (-xy'(x)-y)xy ?
The solution to expand (-xy'(x)-y)xy is -x^2yy'(x)-xy^2