What is expand 1/8 (4(x-1)+36=x) ?

The solution to expand 1/8 (4(x-1)+36=x) is x/2+4=x

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expand 1/8 (4(x-1)+36=x)

expand

\frac{1}{8} (4 (x - 1) + 36 = x)

\frac{x}{2} + 4 = x

Solution steps

\frac{1}{8} (4 (x - 1) + 36 = x)

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{1}{8}, b = 4 (x - 1), c = 36 = x

\frac{1}{8} \cdot 4 (x - 1) + \frac{1}{8} \cdot 36 = x

4 \cdot \frac{1}{8} (x - 1) + 36 \cdot \frac{1}{8} = x

Expand

4 \cdot \frac{1}{8} (x - 1) + 36 \cdot \frac{1}{8} : \frac{x}{2} + 4

\frac{x}{2} + 4 = x

(4 e^{- 2 x} - e^{- 4 x})^{2}

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A (- 5, 5) y B (1, - 1)

What is expand 1/8 (4(x-1)+36=x) ?
The solution to expand 1/8 (4(x-1)+36=x) is x/2+4=x