What is expand (-z/(t^2)+2cos(2t))dt ?

The solution to expand (-z/(t^2)+2cos(2t))dt is -(zdt)/(t^2)+2cos(2t)dt

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expand (-z/(t^2)+2cos(2t))dt

expand

(- \frac{z}{t ^{2}} + 2 cos (2 t)) d t

- \frac{z d t}{t ^{2}} + 2 cos (2 t) d t

Solution steps

(- \frac{z}{t ^{2}} + 2 cos (2 t)) d t

Apply the distributive law:

a (b + c) = ab + a c

a = d t, b = - \frac{z}{t ^{2}}, c = 2 cos (2 t)

= d t (- \frac{z}{t ^{2}}) + d t \cdot 2 cos (2 t)

Apply minus-plus rules

+ (- a) = - a

= - \frac{z}{t ^{2}} d t + 2 cos (2 t) d t

Multiply

\frac{z}{t ^{2}} d t : \frac{z d t}{t ^{2}}

= - \frac{z d t}{t ^{2}} + 2 cos (2 t) d t

(y - 9) - (y + 6 = 4 y)

\frac{( x - y ) ^{2} - z ^{2}}{x + y + z}

\frac{3}{x ( x ^{2} + 1 )}

\frac{f ( x + h ) - f ( x ^{2} )}{h}

1 n (\frac{e ^{4}}{7})

What is expand (-z/(t^2)+2cos(2t))dt ?
The solution to expand (-z/(t^2)+2cos(2t))dt is -(zdt)/(t^2)+2cos(2t)dt