What is expand ((2x-3)(x+1))/((x-1)(x-2)) ?

The solution to expand ((2x-3)(x+1))/((x-1)(x-2)) is (2x^2-x-3)/(x^2-3x+2)

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expand ((2x-3)(x+1))/((x-1)(x-2))

expand

\frac{( 2 x - 3 ) ( x + 1 )}{( x - 1 ) ( x - 2 )}

\frac{2 x ^{2} - x - 3}{x ^{2} - 3 x + 2}

Solution steps

\frac{( 2 x - 3 ) ( x + 1 )}{( x - 1 ) ( x - 2 )}

Expand

(x - 1) (x - 2) : x^{2} - 3 x + 2

= \frac{( 2 x - 3 ) ( x + 1 )}{x ^{2} - 3 x + 2}

Expand

(2 x - 3) (x + 1) : 2 x^{2} - x - 3

= \frac{2 x ^{2} - x - 3}{x ^{2} - 3 x + 2}

(- vx + 2 x) (v + x \frac{d v}{d x})

(x + 2) d x + (y - 2) d y

\frac{x ^{2} + x + 1}{x ( x ^{2} + 1 )}

(- x)^{3}

(3 c e^{3 x} - 5 d e^{- 5 x})^{2}

What is expand ((2x-3)(x+1))/((x-1)(x-2)) ?
The solution to expand ((2x-3)(x+1))/((x-1)(x-2)) is (2x^2-x-3)/(x^2-3x+2)