What is expand ((2x+5)(2x-1))/2 ?

The solution to expand ((2x+5)(2x-1))/2 is 2x^2+4x-5/2

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expand ((2x+5)(2x-1))/2

expand

\frac{( 2 x + 5 ) ( 2 x - 1 )}{2}

2 x^{2} + 4 x - \frac{5}{2}

Solution steps

\frac{( 2 x + 5 ) ( 2 x - 1 )}{2}

Expand

(2 x + 5) (2 x - 1) : 4 x^{2} + 8 x - 5

= \frac{4 x ^{2} + 8 x - 5}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} + 8 x - 5}{2} = \frac{4 x ^{2}}{2} + \frac{8 x}{2} - \frac{5}{2}

= \frac{4 x ^{2}}{2} + \frac{8 x}{2} - \frac{5}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2 x^{2} + \frac{8 x}{2} - \frac{5}{2}

Divide the numbers:

\frac{8}{2} = 4

= 2 x^{2} + 4 x - \frac{5}{2}

\frac{24}{( s ^{2} + 6 s + 18 ) ^{2}}

\frac{1}{( a - s ) ^{2}}

(11 - 1.1 t) d x

\frac{1}{( 1 - x )}

e^{3 x} (e^{3 x} - 8)^{5} d x

What is expand ((2x+5)(2x-1))/2 ?
The solution to expand ((2x+5)(2x-1))/2 is 2x^2+4x-5/2