What is factor 16x^3y^2-8x^2y-24x^4y^2-40x^2y^3 ?

The solution to factor 16x^3y^2-8x^2y-24x^4y^2-40x^2y^3 is 8x^2y(2xy-1-3x^2y-5y^2)

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factor 16x^3y^2-8x^2y-24x^4y^2-40x^2y^3

factor

16 x^{3} y^{2} - 8 x^{2} y - 24 x^{4} y^{2} - 40 x^{2} y^{3}

8 x^{2} y (2 x y - 1 - 3 x^{2} y - 5 y^{2})

Solution steps

16 x^{3} y^{2} - 8 x^{2} y - 24 x^{4} y^{2} - 40 x^{2} y^{3}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{3} y^{2} = x^{2} x yy, x^{4} y^{2} = x^{2} x^{2} yy, x^{2} y^{3} = x^{2} y y^{2}

= 16 x^{2} x yy - 8 x^{2} y - 24 x^{2} x^{2} yy - 40 x^{2} y y^{2}

Rewrite

- 40

5 \cdot 8

Rewrite

- 24

3 \cdot 8

= 2 \cdot 8 x^{2} x yy - 8 x^{2} y + 3 \cdot 8 x^{2} x^{2} yy + 5 \cdot 8 x^{2} y y^{2}

Factor out common term

8 x^{2} y

= 8 x^{2} y (2 x y - 1 - 3 x^{2} y - 5 y^{2})

x - 6 = 8

6 \cdot 6 \cdot 6 \cdot 6 \cdot 6

- 2 + \frac{2}{5}

2 x^{2} - 5 x - 63 = 0

\frac{3}{4} (x + 3) \leq 9

What is factor 16x^3y^2-8x^2y-24x^4y^2-40x^2y^3 ?
The solution to factor 16x^3y^2-8x^2y-24x^4y^2-40x^2y^3 is 8x^2y(2xy-1-3x^2y-5y^2)