What is (f\circ g)(x^2+1)-(x-3) ?

The solution to (f\circ g)(x^2+1)-(x-3) is \circ fgx^2+\circ fg-x+3

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simplify (f\circ g)(x^2+1)-(x-3)

simplify

(f \circ g) (x^{2} + 1) - (x - 3)

\circ f g x^{2} + \circ f g - x + 3

Solution steps

(f \circ g) (x^{2} + 1) - (x - 3)

Remove parentheses:

(a) = a

= f \circ g (x^{2} + 1) - (x - 3)

= \circ f g (x^{2} + 1) - (x - 3)

Expand

f \circ g (x^{2} + 1) : \circ f g x^{2} + \circ f g

= \circ f g x^{2} + \circ f g - (x - 3)

- (x - 3) : - x + 3

= \circ f g x^{2} + \circ f g - x + 3

\frac{1}{( e ^{x} + 1 ) ^{2}}

\frac{- x - 4}{( x + 1 ) ( x - 1 )}

(4 v^{2} y^{2} + y^{2}) (v d y + y d v)

(5 x + 8 (\frac{d y}{d x}))^{2}

(x^{2} - x y + y^{2})^{5}

What is (f\circ g)(x^2+1)-(x-3) ?
The solution to (f\circ g)(x^2+1)-(x-3) is \circ fgx^2+\circ fg-x+3