What is expand ((3h-4)(h+2))/h ?

The solution to expand ((3h-4)(h+2))/h is 3h+2-8/h

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expand ((3h-4)(h+2))/h

expand

\frac{( 3 h - 4 ) ( h + 2 )}{h}

3 h + 2 - \frac{8}{h}

Solution steps

\frac{( 3 h - 4 ) ( h + 2 )}{h}

Expand

(3 h - 4) (h + 2) : 3 h^{2} + 2 h - 8

= \frac{3 h ^{2} + 2 h - 8}{h}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 h ^{2} + 2 h - 8}{h} = \frac{3 h ^{2}}{h} + \frac{2 h}{h} - \frac{8}{h}

= \frac{3 h ^{2}}{h} + \frac{2 h}{h} - \frac{8}{h}

Cancel

\frac{3 h ^{2}}{h} : 3 h

= 3 h + \frac{2 h}{h} - \frac{8}{h}

Cancel

\frac{2 h}{h} : 2

= 3 h + 2 - \frac{8}{h}

- (3 x^{2})

\frac{2}{n ( n + 1 ) ( n + 2 )}

(e^{- x} - e^{- x} \cdot x)^{2}

\frac{( x - 1 ) ^{2}}{x ( x - 4 )}

x (- 13) y (3, 0) z (- 1, - 2)

What is expand ((3h-4)(h+2))/h ?
The solution to expand ((3h-4)(h+2))/h is 3h+2-8/h