What is expand ((t-3)^4)/4 ?

The solution to expand ((t-3)^4)/4 is (t^4)/4-3t^3+(27t^2)/2-27t+81/4

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expand ((t-3)^4)/4

expand

\frac{( t - 3 ) ^{4}}{4}

\frac{t ^{4}}{4} - 3 t^{3} + \frac{27 t ^{2}}{2} - 27 t + \frac{81}{4}

Solution steps

\frac{( t - 3 ) ^{4}}{4}

(t - 3)^{4} = t^{4} - 12 t^{3} + 54 t^{2} - 108 t + 81

= \frac{t ^{4} - 12 t ^{3} + 54 t ^{2} - 108 t + 81}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{t ^{4} - 12 t ^{3} + 54 t ^{2} - 108 t + 81}{4} = \frac{t ^{4}}{4} - \frac{12 t ^{3}}{4} + \frac{54 t ^{2}}{4} - \frac{108 t}{4} + \frac{81}{4}

= \frac{t ^{4}}{4} - \frac{12 t ^{3}}{4} + \frac{54 t ^{2}}{4} - \frac{108 t}{4} + \frac{81}{4}

Divide the numbers:

\frac{12}{4} = 3

= \frac{t ^{4}}{4} - 3 t^{3} + \frac{54 t ^{2}}{4} - \frac{108 t}{4} + \frac{81}{4}

Cancel

\frac{54 t ^{2}}{4} : \frac{27 t ^{2}}{2}

= \frac{t ^{4}}{4} - 3 t^{3} + \frac{27 t ^{2}}{2} - \frac{108 t}{4} + \frac{81}{4}

Divide the numbers:

\frac{108}{4} = 27

= \frac{t ^{4}}{4} - 3 t^{3} + \frac{27 t ^{2}}{2} - 27 t + \frac{81}{4}

2 (3 - x^{2} y) d y

\frac{x ^{m + 2} + ( 2 m - 1 ) x + m}{x - 1}

((x - 3) (x - 5) (x - 6)) \cdot 2

(1 + i^{^{'}})^{12}

(2 x - 1) (\cdot + 2)

What is expand ((t-3)^4)/4 ?
The solution to expand ((t-3)^4)/4 is (t^4)/4-3t^3+(27t^2)/2-27t+81/4