What is expand (x^3-x)/((x^2-3)^2) ?

The solution to expand (x^3-x)/((x^2-3)^2) is (x^3-x)/(x^4-6x^2+9)

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expand (x^3-x)/((x^2-3)^2)

expand

\frac{x ^{3} - x}{( x ^{2} - 3 ) ^{2}}

\frac{x ^{3} - x}{x ^{4} - 6 x ^{2} + 9}

Solution steps

\frac{x ^{3} - x}{( x ^{2} - 3 ) ^{2}}

(x^{2} - 3)^{2} = x^{4} - 6 x^{2} + 9

= \frac{x ^{3} - x}{x ^{4} - 6 x ^{2} + 9}

1 \cdot 1

\frac{x - 1}{3 ( x + 1 )}

\frac{C s}{s C ( L s + R ) + 1}

\frac{- 6}{( - 6 )}

\frac{12}{( s ( s + 1 ) )}

What is expand (x^3-x)/((x^2-3)^2) ?
The solution to expand (x^3-x)/((x^2-3)^2) is (x^3-x)/(x^4-6x^2+9)