What is expand [n(b^{1/(n+1)}-1)]^{n+1} ?

The solution to expand [n(b^{1/(n+1)}-1)]^{n+1} is (nb^{1/(n+1)}-n)^{n+1}

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expand [n(b^{1/(n+1)}-1)]^{n+1}

expand

[n (b^{\frac{1}{n + 1}} - 1)]^{n + 1}

(n b^{\frac{1}{n + 1}} - n)^{n + 1}

Solution steps

(n (b^{\frac{1}{n + 1}} - 1))^{n + 1}

Expand

n (b^{\frac{1}{n + 1}} - 1) : n b^{\frac{1}{n + 1}} - n

= (n b^{\frac{1}{n + 1}} - n)^{n + 1}

\frac{R ( I C + OC )}{2 CR + 1}

8 (y - c) \frac{d y}{d x}

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\frac{[ ( x + h ) ^{3} x ] - x ^{3} - x}{h}

What is expand [n(b^{1/(n+1)}-1)]^{n+1} ?
The solution to expand [n(b^{1/(n+1)}-1)]^{n+1} is (nb^{1/(n+1)}-n)^{n+1}