What are the solutions to the equation w^2-5w-24=0 ?

The solutions to the equation w^2-5w-24=0 are w=8,w=-3

Find the zeros of w^2-5w-24=0

The zeros of w^2-5w-24=0 are w=8,w=-3

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w^{2} - 5 w - 24 = 0

w = 8, w = - 3

Solution steps

w^{2} - 5 w - 24 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 24) = 11

w_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 1}, w_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 1}

w = \frac{- ( - 5 ) + 11}{2 \cdot 1} : 8

w = \frac{- ( - 5 ) - 11}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

w = 8, w = - 3

0.6 x + 0.8 = 1.4

\frac{3}{2}

\frac{2}{5} \cdot 9

(4 - x^{\frac{2}{3}})^{\frac{3}{2}}

\frac{- 15 \cdot - 5}{3}

What are the solutions to the equation w^2-5w-24=0 ?
The solutions to the equation w^2-5w-24=0 are w=8,w=-3
Find the zeros of w^2-5w-24=0
The zeros of w^2-5w-24=0 are w=8,w=-3