What is expand (8(2-2x)^3)/3 ?

The solution to expand (8(2-2x)^3)/3 is -(64x^3)/3+64x^2-64x+64/3

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expand (8(2-2x)^3)/3

expand

\frac{8 ( 2 - 2 x ) ^{3}}{3}

- \frac{64 x ^{3}}{3} + 64 x^{2} - 64 x + \frac{64}{3}

Solution steps

\frac{8 ( 2 - 2 x ) ^{3}}{3}

(2 - 2 x)^{3} = 8 - 24 x + 24 x^{2} - 8 x^{3}

= \frac{8 ( - 8 x ^{3} + 24 x ^{2} - 24 x + 8 )}{3}

Expand

8 (8 - 24 x + 24 x^{2} - 8 x^{3}) : 64 - 192 x + 192 x^{2} - 64 x^{3}

= \frac{64 - 192 x + 192 x ^{2} - 64 x ^{3}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{64 - 192 x + 192 x ^{2} - 64 x ^{3}}{3} = \frac{64}{3} - \frac{192 x}{3} + \frac{192 x ^{2}}{3} - \frac{64 x ^{3}}{3}

= \frac{64}{3} - \frac{192 x}{3} + \frac{192 x ^{2}}{3} - \frac{64 x ^{3}}{3}

Divide the numbers:

\frac{192}{3} = 64

= \frac{64}{3} - 64 x + 64 x^{2} - \frac{64 x ^{3}}{3}

Rewrite in standard form

= - \frac{64 x ^{3}}{3} + 64 x^{2} - 64 x + \frac{64}{3}

- 4 (x + 2) - \frac{1}{3} (- 12 x = 3)

U (- 3, 1, - 1) \cdot v (- 4, 5, 0)

3 x + 2 (x^{2} - y e)

3 b + (3 b - 2)

\frac{1}{( x + 1 ) ^{6}}

What is expand (8(2-2x)^3)/3 ?
The solution to expand (8(2-2x)^3)/3 is -(64x^3)/3+64x^2-64x+64/3