What is expand (64(x+1)(2x+1))/(x^2) ?

The solution to expand (64(x+1)(2x+1))/(x^2) is 128+(192)/x+(64)/(x^2)

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expand (64(x+1)(2x+1))/(x^2)

expand

\frac{64 ( x + 1 ) ( 2 x + 1 )}{x ^{2}}

128 + \frac{192}{x} + \frac{64}{x ^{2}}

Solution steps

\frac{64 ( x + 1 ) ( 2 x + 1 )}{x ^{2}}

Expand

64 (x + 1) (2 x + 1) : 128 x^{2} + 192 x + 64

= \frac{128 x ^{2} + 192 x + 64}{x ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{128 x ^{2} + 192 x + 64}{x ^{2}} = \frac{128 x ^{2}}{x ^{2}} + \frac{192 x}{x ^{2}} + \frac{64}{x ^{2}}

= \frac{128 x ^{2}}{x ^{2}} + \frac{192 x}{x ^{2}} + \frac{64}{x ^{2}}

Cancel

\frac{128 x ^{2}}{x ^{2}} : 128

= 128 + \frac{192 x}{x ^{2}} + \frac{64}{x ^{2}}

Cancel

\frac{192 x}{x ^{2}} : \frac{192}{x}

= 128 + \frac{192}{x} + \frac{64}{x ^{2}}

\frac{x ( x + 3 )}{( x - 4 )}

\frac{( x - 3 ) ( x + 4 )}{x}

e^{t (l n (t) - s)}

q (x) (x^{2} - 9 = 0)

e^{2 x^{2} - 3 x + 2} (4 x - 3)

What is expand (64(x+1)(2x+1))/(x^2) ?
The solution to expand (64(x+1)(2x+1))/(x^2) is 128+(192)/x+(64)/(x^2)