What is expand e^{3t-12}h(t-4) ?

The solution to expand e^{3t-12}h(t-4) is e^{3t-12}th-4e^{3t-12}h

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expand e^{3t-12}h(t-4)

expand

e^{3 t - 12} h (t - 4)

e^{3 t - 12} t h - 4 e^{3 t - 12} h

Solution steps

e^{3 t - 12} h (t - 4)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{3 t - 12} h, b = t, c = 4

= e^{3 t - 12} h t - e^{3 t - 12} h \cdot 4

= e^{3 t - 12} t h - 4 e^{3 t - 12} h

\frac{x}{( x - 3 ) ( x ^{2} + 4 ) ^{9}}

\frac{1}{s ( b s + 1 )}

(- 20 x + 4 y = 12) 9

(3 y d x + 6 d x - x d y = 0) \frac{d y}{x d x}

2 (x + 1) (ln (x + 1)) + x + 1

What is expand e^{3t-12}h(t-4) ?
The solution to expand e^{3t-12}h(t-4) is e^{3t-12}th-4e^{3t-12}h